TEST - 4

1.  Salman was twice as old as Alyan 10 years back. How old is Alyan today if Salman will be 40 years old 10 years hence

(a) 18     (b) 25     (c) 15     (d) 20

 

 Reason:  Salman’s age today = 30 years.

Salman’s age 10 years back = 20 years.

Alyan’s age 10 years back = 10 years.

Alyan’s age today =20 year.

 

1.  Salman was twice as old as Alyan 10 years back. How old is Alyan today if Salman will be 40 years old 10 years hence

(a) 18     

(b) 25     

(c) 15     

(d) 20

 

 Reason:  Salman’s age today = 30 years.

Salman’s age 10 years back = 20 years.

Alyan’s age 10 years back = 10 years.

Alyan’s age today =20 year.

 

2. In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is:

(a) 35     (b) 37     (c) 39     (d) 41

 

Reason:   Let B’s age = x years.

Then, A’s age = (x+ 9) years.

(x+9+10)=2(x—10)

Hence x=39; Present age of B = 39 year.

 

2. In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is:

(a) 35     

(b) 37     

(c) 39     

(d) 41

 

Reason:   Let B’s age = x years.

Then, A’s age = (x+ 9) years.

(x+9+10)=2(x—10)

Hence x=39; Present age of B = 39 year.

 

3. Ten years ago A was half of B in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

(a) 30     (b) 35     (c) 37     (d) 41

 

Reason: Let A’s age 10 years ago = x years.

Then, B’s age 10 years ago = 2x years.

(x + 10) / (2x+ 10) = 3/4

=> x = 5.

So, the total of their present ages =(x + 10 + 2x + 10)

= (3x + 20) = (3×5 + 20) = 35 years.

 

3. Ten years ago A was half of B in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

(a) 30     

(b) 35     

(c) 37     

(d) 41

 

Reason: Let A’s age 10 years ago = x years.

Then, B’s age 10 years ago = 2x years.

(x + 10) / (2x+ 10) = 3/4

=> x = 5.

So, the total of their present ages =(x + 10 + 2x + 10)

= (3x + 20) = (3×5 + 20) = 35 years.

 

4. Abdullah was thrice as old as Saqib 6 years back. Abdullah will be times as old as Saqib 6 years hence. How old is Saqib today?

(a) 12     (b) 16     (c) 18     (d) 24

 

Reason:  Let Saqib age 6 years back = x.

Then, Abdullah age 6 years back = 3x.

(5/3) * (X + 6 + 6) = (3X + 6 + 6)

So 5(x+ 12) = 3(3x+ 12),

So x=6.

Saqib  Age = (x+ 6) years = 12 years

 

4. Abdullah was thrice as old as Saqib 6 years back. Abdullah will be times as old as Saqib 6 years hence. How old is Saqib today?

(a) 12     

(b) 16     

(c) 18    

(d) 24

 

Reason:  Let Saqib age 6 years back = x.

Then, Abdullah age 6 years back = 3x.

(5/3) * (X + 6 + 6) = (3X + 6 + 6)

So 5(x+ 12) = 3(3x+ 12),

So x=6.

Saqib  Age = (x+ 6) years = 12 years

 

5.  Six years ago, the ratio of the ages of Kamal and Saim was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Saim age at present?

(a) 10 YEARS     (b) 12 YEARS     (c) 14 YEARS     (d) 16 YEARS

 

REASON: Let six years ago the age of Kamal and Saim are 6x and 5x

resp.

then,

=>(6x+6)+4 /(5x+6)+4=11/10

<=>10(6x+10)=11(5x+10)

<=>5x=10=>x=2

So Saim age is (5x+6) = (5×2+6) = 16.

 

5.  Six years ago, the ratio of the ages of Kamal and Saim was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Saim age at present?

(a) 10 YEARS    

(b) 12 YEARS     

(c) 14 YEARS    

(d) 16 YEARS

 

REASON: Let six years ago the age of Kamal and Saim are 6x and 5x

resp.

then,

=>(6x+6)+4 /(5x+6)+4=11/10

<=>10(6x+10)=11(5x+10)

<=>5x=10=>x=2

So Saim age is (5x+6) = (5×2+6) = 16.

 

6.  Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is

(a) 90     (b) 98     (c) 120     (d) DATA IS NOT ADEQUATE

 

6.  Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is

(a) 90     

(b) 98     

(c) 120     

(d) DATA IS NOT ADEQUATE

 

7.  Total of the ages of A, B and C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

(a) 25     (b) 30     (c) 45     (d) 60

 

REASON: Let their ages 10 years ago is x, 2x and 3x years.

10 + 2x + 10 + 3x + 10 = 90 hence x= 10

B’s present age = (2x + 10) =30 years.

 

7.  Total of the ages of A, B and C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

(a) 25     

(b) 30     

(c) 45     

(d) 60

 

REASON: Let their ages 10 years ago is x, 2x and 3x years.

10 + 2x + 10 + 3x + 10 = 90 hence x= 10

B’s present age = (2x + 10) =30 years.

 

8. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

(a) 20 YEARS     (b) 21 YEARS     (c) 22 YEARS     (d) 24 YEARS 

REASON:  Let the son’s present age be x years. Then, man’s present age = (x + 24) years

=> (x + 24) + 2 = 2(x + 2)

=> x + 26 = 2x + 4   So, x = 22.

 

8. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

(a) 20 YEARS     

(b) 21 YEARS     

(c) 22 YEARS    

(d) 24 YEARS 

REASON:  Let the son’s present age be x years. Then, man’s present age = (x + 24) years

=> (x + 24) + 2 = 2(x + 2)

=> x + 26 = 2x + 4   So, x = 22.

 

9. Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.

(a) 16, 35, 36     (b) 12, 28, 36     (c) 16, 28, 27     (d) 16, 28, 36

 

REASON:  Let the present ages are 4x, 7x, 9x.

=> (4x-8) + (7x-8) + (9x-8) = 56

=> 20x = 80

=> x = 4

So their present ages are: 16, 28, and 36.

 

9. Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.

(a) 16, 35, 36     

(b) 12, 28, 36     

(c) 16, 28, 27     

(d) 16, 28, 36

 

REASON:  Let the present ages are 4x, 7x, 9x.

=> (4x-8) + (7x-8) + (9x-8) = 56

=> 20x = 80

=> x = 4

So their present ages are: 16, 28, and 36.

 

10. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is son’s present age?

(a) 21 YEARS     (b) 22 YEARS     (c) 23 YEARS     (d) 24 YEARS

 

REASON; Let’s Son age is x, then Father age is x+24.

=> 2(x+2) = (x+24+2)

=> 2x+4 = x+26

=> x = 22 years.

10. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is son’s present age?

(a) 21 YEARS    

(b) 22 YEARS     

(c) 23 YEARS    

(d) 24 YEARS

 

REASON; Let’s Son age is x, then Father age is x+24.

=> 2(x+2) = (x+24+2)

=> 2x+4 = x+26

=> x = 22 years.

Age Problem TEST - 4

4

PROBLEM OF AGE TEST-4 (QM)

PROBLEM OF AGE TEST-4 (QM)

The number of attempts remaining is 100

1 / 10

1. Ramees and Shan’s average age is 65 years. The average age of ramees, Shan and Junaid is 53
years. What is the age of Junaid?

2 / 10

2. Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years
from now. What was ratio of ages of Tanya and her grandfather 8 years ago.

3 / 10

3. Rohan's age is five times ALI and seven-eighteenth of Meena’s age. The sum of the ages of all three
of them is 132 years. How much younger is Ajay to Meena?

4 / 10

4. Average age of a family of 4 members was 19 years, 4 years back. Birth of a new child kept the
average age of the family same even today. How old is the child today?

5 / 10

5. Age of Umar will be 4 times the age of Raima in 6 years from today. If ages of Umar and Marium
are 7 times and 6 times the age of raima respectively, what is present age of Umar?

6 / 10

6. The average age of 10 students and their teacher is 15 years. The average age of the first seven
students is 15 yr and that of the last three is 11 yr. What is the teacher's age?

7 / 10

7. The present ages of Amna and Nida are 59 and 37 years, respectively. What was the ratio of the
ages of Nida and Amna 13 years ago?

8 / 10

8. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the
age of his mother. How old is the mother at present

9 / 10

9. Rohan is as much younger than Ahmed as he is older than Meena. The sum of ages of Ahmed and
Meena is 108 years. How old is Rohan?

10 / 10

10. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five
times the age of the son. After 6 years, son's age will be

Your score is

Preparation is FUN here...

LinkedIn Facebook Twitter VKontakte
0%

Exit

Thank You for Your Judgement!!!

NEXT STEP

AGING TEST - 5

NEXT STEP

AGING TEST - 5
NEXT STEP

PREVIOUS STEP

AGING TEST - 3

PREVIOUS STEP

AGING TEST - 3
PREVIOUS STEP