TEST - 8

1.  The average of the ages of a man and his daughter is 34 years. If the respective ratio of their ages four years from now is 14: 5,what is daughter’s present age?

(a)  10 years  (b)  12 years   (c)   18 years      (d)  none of these

Explanation: Average age of man and his daughter = 34 years

Their total age = (34 × 2) years = 68 years

Let man’s age be x years,

Then daughter age = (68 – x) years

x+468−x+4=1455(x+4)=14(72−x)5x+20=1008−14x19x=988x=52

  Daughter’s present age

= (68 – 52) years   =   = 16 years

1.  The average of the ages of a man and his daughter is 34 years. If the respective ratio of their ages four years from now is 14: 5,what is daughter’s present age?

(a)  10 years  

(b)  12 years   

(c)   18 years      

(d)  none of these

Explanation: Average age of man and his daughter = 34 years

Their total age = (34 × 2) years = 68 years

Let man’s age be x years,

Then daughter age = (68 – x) years

x+468−x+4=1455(x+4)=14(72−x)5x+20=1008−14x19x=988x=52

  Daughter’s present age

= (68 – 52) years  = 16 years

2. The age of a father 10 years ago was thrice the age of his son. 10 years hence, the father’s age will be twice that of his son. The ratio of their present age is = ?

(a) 8 : 5    (b)  7 : 3  (c)  9 : 5    (d)  5 : 2

Explanation: Let son’s age 10 years ago be x years

Then, father age 10 years ago = 3x years

Son’s age now = (x + 10) years,

Father age now = (3x+ 10) years

(3x+10)+10=2[(x+10)+10]3x+20=2(x+20)3x+20=2x+40x=20

Ratio of present ages of father and son

 = 3x+10x+10=3×20+1020+10=7030=73=7:3

 

2. The age of a father 10 years ago was thrice the age of his son. 10 years hence, the father’s age will be twice that of his son. The ratio of their present age is = ?

(a) 8 : 5    

(b)  7 : 3  

(c)  9 : 5    

(d)  5 : 2

Explanation: Let son’s age 10 years ago be x years

Then, father age 10 years ago = 3x years

Son’s age now = (x + 10) years,

Father age now = (3x+ 10) years

(3x+10)+10=2[(x+10)+10]3x+20=2(x+20)3x+20=2x+40x=20

Ratio of present ages of father and son

 = 3x+10x+10=3×20+1020+10=7030=73=7:3

3. At present Subhan’s age is twice the age of his daughter. After 6 year from now, the ratio of the ages of Subhan and his daughter will be 23: 13. What is the present age of Subhan?

(a)  36 years    (b)  40 years   (c)   46 years     (d) none of these

Explanation: Let daughter’s age be x years.

Sobhan’s age = 2x years

2x+6x+6=231313(2x+6)=23(x+6)26x+78=23x+1383x=60x=20

 Present age of Subhan = 2x years

 = (2×20) years  = 40 years

 

3. At present Subhan’s age is twice the age of his daughter. After 6 year from now, the ratio of the ages of Subhan and his daughter will be 23: 13. What is the present age of Subhan?

(a)  36 years    

(b)  40 years   

(c)   46 years     

(d) none of these

Explanation: Let daughter’s age be x years.

Sobhan’s age = 2x years

2x+6x+6=231313(2x+6)=23(x+6)26x+78=23x+1383x=60x=20

 Present age of Subhan = 2x years

 = (2×20) years  = 40 years

4. Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

(a) 12 years   (b)  13 years   (c)  14 years      (d)  15 years  

Explanation: Let son’s age 10 years ago be x years.

Then, man’s age 10 years ago = 7x years

Son’s present age = (x + 10) years,

Man’s present age = (7x + 10) years

2[(7x+10)+2] = 5[(x+10)+2]2(7x+12)=5(x+12)14x+24=5x+609x=36x=4

 Son’s present age = (x + 10) years

= (4 + 10) years   = 14 years

4. Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

(a) 12 years   

(b)  13 years   

(c)  14 years      

(d)  15 years  

Explanation: Let son’s age 10 years ago be x years.

Then, man’s age 10 years ago = 7x years

Son’s present age = (x + 10) years,

Man’s present age = (7x + 10) years

2[(7x+10)+2] = 5[(x+10)+2]2(7x+12)=5(x+12)14x+24=5x+609x=36x=4

 Son’s present age = (x + 10) years

= (4 + 10) years     = 14 years

5.  The ages of Samina and  Sana are in the ratio of 7:3 respectively. After 6 years, the ratio of their ages will be 5:3. What is the difference in their ages?

(a) 6 years      (b)  8   years   (c) 10 years       (d)12 years  

Explanation: Let Samina’s age be 7x years.

Then, Sana’s age = 3x years

7x+63x+6=533(7x+6)=5(3x+6)21x+18=15x+306x+12x=2

 Difference in their ages = (7x – 3x) years

= 4x years    = (4 × 2) years     = 8 years

5.  The ages of Samina and  Sana are in the ratio of 7:3 respectively. After 6 years, the ratio of their ages will be 5:3. What is the difference in their ages?

(a) 6 years      (b)  8   years   (c) 10 years       (d)12 years  

Explanation: Let Samina’s age be 7x years.

Then, Sana’s age = 3x years

7x+63x+6=533(7x+6)=5(3x+6)21x+18=15x+306x+12x=2

 Difference in their ages = (7x – 3x) years

= 4x years    = (4 × 2) years   = 8 years

6.  The ages of A and B are presently in the ratio of 5: 6 respectively. Six years hence, this ratio became 6: 7 respectively. What was B’s age 5 years ago?

(a)  25 years    (b)  30 years   (c)  31 years      (d)  36 years  

Explanation: Let A’s age be 5x years.

Then, B’s age = 6x years

5x+66x+6=677(5x+6)=6(6x+6)35x+42=36x+36x=6

 B’s age 5 years ago = (6x – 5) years

= (6 × 6 – 5) years  = 31 years

6.  The ages of A and B are presently in the ratio of 5: 6 respectively. Six years hence, this ratio became 6: 7 respectively. What was B’s age 5 years ago?

(a)  25 years    

(b)  30 years   

(c)  31 years      

(d)  36 years  

Explanation: Let A’s age be 5x years.

Then, B’s age = 6x years

5x+66x+6=677(5x+6)=6(6x+6)35x+42=36x+36x=6

 B’s age 5 years ago = (6x – 5) years

= (6 × 6 – 5) years    = 31 years

7.  The sum of the ages of a daughter and her mother is 56 years. After 4 years, the age of the mother will be three times that of the daughter. At present their ages are ?

(a)  10 years  , 46 years    (b)  12 years  , 44 years   (c)   11 years  , 45 years     (d)  13 years  , 43 years  

Explanation:  Let daughter’s age be x years.

Then, mother’s age = (56 −x) years

(56−x)+4=3(x+4)60−x=3x+124x=48x=12

  Daughter’s age = 12 years

And the mother’s age = (56 −12) = 44 years

 

7.  The sum of the ages of a daughter and her mother is 56 years. After 4 years, the age of the mother will be three times that of the daughter. At present their ages are ?

(a)  10 years  , 46 years    

(b)  12 years  , 44 years   

(c)   11 years  , 45 years     

(d)  13 years  , 43 years  

Explanation:  Let daughter’s age be x years.

Then, mother’s age = (56 −x) years

(56−x)+4=3(x+4)60−x=3x+124x=48x=12

  Daughter’s age = 12 years

And the mother’s age = (56 −12) = 44 years

8. The present age of son is half of the present age of his mother. Ten years ago, his mother’s age was thrice the age of her son. What is the present age of the son?

(a) 20 years      (b)  25 years   (c)    30 years    (d)  40 years  

Explanation: Let mother’s age be 2x years,

Then, son’s age = x years

(2x−10)=3(x−10)2x−10=3x−30x=20

Son’s age = 20 years

 

8. The present age of son is half of the present age of his mother. Ten years ago, his mother’s age was thrice the age of her son. What is the present age of the son?

(a) 20 years      

(b)  25 years   

(c)    30 years    

(d)  40 years  

Explanation: Let mother’s age be 2x years,

Then, son’s age = x years

(2x−10)=3(x−10)2x−10=3x−30x=20

Son’s age = 20 years

9. Rohan’s son’s age is 1/3 of Rohan’s wife’s age. Rohan’s wife’s age is of 4/5 of Rohan’s age and Rohan’s age is of3/ 5 of Rohan’s father’s age. Find the age of Rohan’s son, if Rohan’s father is 50 years old?

(a) 6 years     (b)  8 years   (c)  10 years      (d)  12 years  

Explanation: Rohan’s father’s age = 50 years, Rohan’s age = (35×50)years = 30 years Rohan’s wife’s age = (45×30)years = 24 years Rohan’s son’s age = (13×24)years = 8 years

 

9. Rohan’s son’s age is 1/3 of Rohan’s wife’s age. Rohan’s wife’s age is of 4/5 of Rohan’s age and Rohan’s age is of3/ 5 of Rohan’s father’s age. Find the age of Rohan’s son, if Rohan’s father is 50 years old?

(a) 6 years     

(b)  8 years   

(c)  10 years      

(d)  12 years  

Explanation: Rohan’s father’s age = 50 years, Rohan’s age = (35×50)years = 30 years Rohan’s wife’s age = (45×30)years = 24 years Rohan’s son’s age = (13×24)years = 8 years

10. Rayyan got married 8 years ago. His present age is 6/5 times his age   at the time of his marriage. Rayyan’s sister was 10 years younger to him at the time of his marrige. The age of Rayyan’s sister is = ?

(a) 32 years     (b)  38 years   (c)  36 years      (d)  40 years  

Explanation: Let Rayyan’s age 8 years ago be x years,

Then, present age = (x + 8) years

x+8=65x5x+40=6xx=40

Rayyan’s sister’s age 8 years ago

= (40 – 10) years   = 30 years   

 His sister’s age now

= (30+8) years    = 38 years

10. Rayyan got married 8 years ago. His present age is 6/5 times his age   at the time of his marriage. Rayyan’s sister was 10 years younger to him at the time of his marrige. The age of Rayyan’s sister is = ?

(a) 32 years     (b)  38 years   (c)  36 years      (d)  40 years  

Explanation: Let Rayyan’s age 8 years ago be x years,

Then, present age = (x + 8) years

x+8=65x5x+40=6xx=40

Rayyan’s sister’s age 8 years ago

= (40 – 10) years    = 30 years

 His sister’s age now

= (30+8) years   = 38 years

Age Problem TEST - 8

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PROBLEM OF AGE TEST-8 (QM)

PROBLEM OF AGE TEST-8 (QM)

The number of attempts remaining is 100

1 / 10

1. Rayyan got married 8 years ago. His present age is 6/5 times his age   at the time of his marriage. Rayyan’s sister was 10 years younger to him at the time of his marrige. The age of Rayyan's sister is = ?

2 / 10

2. The ages of Samina and  Sana are in the ratio of 7:3 respectively. After 6 years, the ratio of their ages will be 5:3. What is the difference in their ages?

3 / 10

3. Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

4 / 10

4. The sum of the ages of a daughter and her mother is 56 years. After 4 years, the age of the mother will be three times that of the daughter. At present their ages are ?

5 / 10

5. At present Subhan's age is twice the age of his daughter. After 6 year from now, the ratio of the ages of Subhan and his daughter will be 23: 13. What is the present age of Subhan?

6 / 10

6. The present age of son is half of the present age of his mother. Ten years ago, his mother's age was thrice the age of her son. What is the present age of the son?

7 / 10

7. Rohan's son's age is 1/3 of Rohan's wife's age. Rohan's wife's age is of 4/5 of Rohan's age and Rohan's age is of3/ 5 of Rohan's father's age. Find the age of Rohan’s son, if Rohan's father is 50 years old?

8 / 10

8. The age of a father 10 years ago was thrice the age of his son. 10 years hence, the father's age will be twice that of his son. The ratio of their present age is = ?

9 / 10

9. The average of the ages of a man and his daughter is 34 years. If the respective ratio of their ages four years from now is 14: 5,what is daughter's present age?

10 / 10

10. The ages of A and B are presently in the ratio of 5: 6 respectively. Six years hence, this ratio became 6: 7 respectively. What was B's age 5 years ago?

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